If two coins are tossed, then find the probability of the event that at least one head turns up.

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#### Solution

Let S be the sample space.

Then S = {HH, HT, TH, TT}

∴ n(S) = 4

Let A be the event where at least one tail turns up.

At least one head means 1 head or more than 1 heads.

If S = {HH, HT, TH, TT}

∴ A = {HT, TH, HH}

∴ n(A) = 3

n(A) 3

Now, ` P(A)=(n(A))/(n(s))=3/4`

Concept: Basic Ideas of Probability

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