Question

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Let the $CP$ and $SP$ of the bicycle be $x$ and $y$ respectively.

For the case, when $SP=y,$

$gain%120.12xy =CPSP−CP ×100=xy−x ×100=y−x=1.12x…(i) $

For the case, when $SP=y+16,$

$gain%200.2x0.2x0.08xx =CPSP−CP ×100=xy+16−x ×100=1.12x+16−x=0.12x+16=16=Rs.200 $

By using equation $(i),$

$y =1.12x=1.12×200=Rs.224 $

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